A stone is thrown vertically upward with a velocity of 40m/s and ia caught back taking 10m/s .calculate the maximum height reached total distances coverd by th stone... please answer with full solution. :-) (┬╗:<br />
Answers
Answered by
1
u = 40
v = 0 , g= - 10
by using the formula v^2 - u^2 = 2 gh
0-40^2 = 2(-10)h
-1600 = -20h
-1600/-20 = h
h = 80m
v = 0 , g= - 10
by using the formula v^2 - u^2 = 2 gh
0-40^2 = 2(-10)h
-1600 = -20h
-1600/-20 = h
h = 80m
Similar questions