Question

A stone is thrown vertically upward with an initial speed of 19.5 m/s. It will rise to a maximum

height of:

A. 4.9 m

B. 9.8 m

C. 19.4 m

D. 38.8 m

E. none of these​

Answer 1

Answer:

.c hope it may help you...

Answer 2

Answer:

The stone will raise to a maximum height of (C)19.4m

Explanation:

Given that,

The stone is thrown with a velocity of 19.5m/s vertically upward.

The kinematic equation for this motion is given by

$h = ut + \frac{1}{2} gt {}^{2}$

u=0(treating this as freely falling body).Therefore,

$h = \frac{1}{2} gt {}^{2} = > t = \sqrt{\frac{2h}{g} }$

The equation for velocity is given as

$v = u - gt \\ 0 = u - gt = > t = \frac{u}{g}$

Equating the time obtained from both the relations,we get

$\frac{u}{g} = \sqrt{ \frac{2h}{g} } \\ = > h = \frac{u {}^{2} }{2g}$

Substituting known values,we get

$h = \frac{19.5 {}^{2} }{2 \times 9.81} = 19.38m≈19.4m$

Therefore,The stone will raise to a maximum height of 19.4m(option C)

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