A stone is thrown vertically upward with an initial speed of 19.5 m/s. It will rise to a maximum
height of:
A. 4.9 m
B. 9.8 m
C. 19.4 m
D. 38.8 m
E. none of these
Answers
Answered by
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Explanation:
Vi= 19.4 approximately =19.5
Vf= 0m/s
a= - 9.8 m/s^2
d=?
Since we have those informations. Use
Vf^2 = 2ad + vi^2
When it reaches the maximum height, it's final velocity is 0 m/s
(0m/s)^2 = 2(-9.8m/s^2) d + (19.5m/s)^2 - 380.25m^2 /s^2 = (-19.6m/s^2) d
d= 19.4m
Here is your answer
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