Question

A stone is thrown vertically upward with an initial speed of 20 m/s. When it returns, it falls into a hole that is 10.0 m deep. How long (in seconds) is the rock in the air, from the instant it is tossed until it hits the bottom of the hole? Use -9.80 m/s2 for the local acceleration due to gravity and assume no significant air resistance.

Answer 1

Answer:

4.515

Explanation:

t1=u/a=2sec

t2=(2s/a)^.5=2.5

Answer 2

Explanation:

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