Physics, asked by jtanmay1743, 11 months ago

A stone is thrown vertically upward with an initial velocity u from the top of a tower, reaches the ground with a velocity 3u. The height of the tower is:

Answers

Answered by ramatholisaiah

4

Answer:

height of tower=4u^2/g

Answered by plschowdary2009

0

Answer:

4u²/g

Explanation:

Formula Used is (v²-u²)/2g

[(3u)²-(u²)]/2g

(9u²-u²)/2g

8u²/2g

4u²/g

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