Question

A stone is thrown vertically upward with an initial velocity of 40m/s. Taking g =
10m/s. Find the net displacement and total distance covered by it?​

Answer 1

Answer:displacement is zero

Distance is 8m

Explanation:

Answer 2

Initial velocity u = 40 m/s

At peak point (highest point) velocity will become zero

Final velocity v = 0 m/s

Taking +ve y axis in upward direction and -ve y axis in downward direction

By V² = U² + 2gh  

     0 = 40*40 + 2*(-10)*h ................{ I have taken g = -10 because it is acting

                                                                                             downwards}

h = 80m

After reaching height of 80 meters stone will start coming downwards and will again cover a distance of 80 meters. So, total distance covered by stone = 80 + 80 = 160 meters.

Since initial and final position of stone are same displacement will be zero.

I hope you unterstood the part where i took +ve y axis in upward direction and -ve y axis in downward direction. You can take coordinate axis as per you choice.