A stone is thrown vertically upward with an initial velocity 49m/s from the top of a tower and teaches the ground after 12 seconds. Find the height of the tower
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Explanation:
Answer:
height of the tower = 117.6 m
Explanation:
u = 49 m/s
a = - 9.8 m/sq-sec
t = 12 s
net displacement,
s = ut + (1/2) a t^2
= 49×12 - (1/2) 9.8 × 12×12
= 49×12 (1 - 1.2)
= - 49 × 12 × 0.2
= - 117.6 m
so, height of the tower = 117.6 m
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