a stone is thrown vertically upward with an initial velocity of 40m\s.F ma the maximum height reached by the stone.what is the net displacement and the total distance covered by the stone?
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what is the net displacement and the total distance covered by tha stone a stone is thrown vertically upward with an initial velocity.
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where V = 0
U = 40 m/s
a = -g m/s² = -10 m/s²
0 = (40)² -2 × 10 × S
- S = 80 m .
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