Question

a stone is thrown vertically upward with an initial velocity of 40 m/s. taking G= 10 m/s^2. find the maximum height reached by the stone . what is the stone net displacement and the total distance covered by the stone ?

Answer 1

Answer:

Height = 80m

Displacement = 40m

Answer 2

Answer:

80 meter

Explanation:

We have,

Initial velocity (u) = 40m/s and g = -10m/s^2

also final velocity (v) = 0 m/s (At highest point)

v^2 = u^2 + 2ah

0 = 1600 - 2 * 10 * h

20h = 1600

h = 80m.

Hence, maximum height reached by stone is 80m.

And total displacement is 0m and total distance is (80m + 80m) = 160m