Question

A stone is thrown vertically upward with an initial velocity of 40m/s. Taking g=10m/s2, find the maximum height reached by the stone. What is the net displacement and the total distance covered by the stone?​

Answer 1

Answer with Explaination: Initial Velocity u=40

Fianl velocity v=0

Height, s=?

By third equation of motion

v  

2

−u  

2

=2gs

0−40  

2

=−2×10×s

s=  

20

160

​  

 

⇒s=80m/s

Toatl distance travelled by stone = upward distance + downwars distance =2×s=160m

Total Diaplacement =0, Since the initial and final point is same.

it may help you

Answer 2

Answer:

The maximum height is 80 m and the total distance covered by the stone is 160 m and the displacement is zero.