a stone is thrown vertically upward with an initial velocity of 40 m/s. taking g=10m/s^2, find the maximum height reached by the stone.what is the net displacement and the total distance covered by the stone
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The maximum height is 80 m and the total distance covered by the stone is 160 m and the displacement is zero. Hence, The maximum height is 80 m and the total distance covered by the stone is 160 m and the displacement is zero.
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The maximum height is 80 m and the total distance covered by the stone is 160 m and the displacement is zero. Hence, The maximum height is 80 m and the total distance covered by the stone is 160 m and the displacement is zero.
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