Question

a stone is thrown vertically upward with an initial velocity 14 m find the maximum height reached a​

Answer 1

Answer:

the maximum height is calculated by u^2/2g

= 14*14/ 2*10

=196/20

=9.8 m/s

Answer 2

Explanation:

Answer:

$\setlength{\unitlength}{1mm}\begin{picture}(8,2)\thicklines\multiput(9,1.5)(1,0){50}{\line(1,2){2}}\multiput(35,7)(0,4){13}{\line(0,1){2}}\put(10.5,6){\line(3,0){50}}\put(35,60){\circle*{10}}\put(37,7){\large\sf{u = 14m/s}}\put(37,55){\large\sf{v = 0 m/s}}\put(20,61){\large\textsf{\textbf{Stone}}}\end{picture}$

• Initial Velocity ( u ) = 14 m/s

• Final Velocity ( v ) = 0 m/s

• Gravity = - 10 m/s²

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$\underline{\bigstar\:\textsf{By Third Equation of Gravity :}}$

$:\implies\sf v^2-u^2=2gh\\\\\\:\implies\sf (0)^2-(14)^2=2 \times (-10) \times h\\\\\\:\implies\sf 0- 196=-20 \times h\\\\\\:\implies\sf -196 = - 20 \times h\\\\\\:\implies\sf \dfrac{ - 196}{ - 20} = h\\\\\\:\implies\underline{\boxed{\sf h = 9.8 \:metres}}$

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