Question

A stone is thrown vertically upward with an initial velocity of 40 m/so. taking g=10 meters /square .find the maximum height reached by the the stone .what is net displacement and the total distance covered by the stone?

Answer 1

h= 80 m
dispacement 0m
total distance will be 80m

Answer 2

hey...

u = 40 m/s

g = 10 m/s^2

height= ?

v= 0

by using

2gs = v^2 - u^2

2× 10 × s = 0^2 - 40^2

20 × s = - 1600

s= 1600/20

s = 80 m.

distance = 80 + 80 = 160( upward + downward direction)

displacement = 0