Question

. A stone is thrown vertically upward with an initial velocity of 40m/s. Taking

g = 10m/s2

, find the maximum height reached by the stone. What is the net

displacement and the total distance covered by the stone?
please I need accurate answer I will mark you brainlist ​

Answer 1

Answer:

ANSWER

Initial Velocity u=40

Fianl velocity v=0

Height, s=?

By third equation of motion

v2−u2=2gs

0−402=−2×10×s

s=20160

⇒s=80m/s

Toatl distance travelled by stone = upward distance + downwars distance =2×s=160m

Total Diaplacement =0, Since the initial and final point is same.