Question

A stone is thrown vertically upward with an initial velocity of 80m/s.find the hieght reached by the stone​

Answer 1

Answer:

The height reached by the stone is 320m.

Explanation:

u = 80m/s v = 0m/s g = -10m/s^-2

v^2 - u^2 = 2gh

0 - (80)^2 = 2 × -10 × h

h × -20 = -6400

h = -6400 / -20

h = 320m