Question

A stone is thrown vertically upward with an initial velocity u from the top of a tower. It reaches the ground with a velocity 3u. The height of the tower is​

Answer 1

H = (v² - u²) / (2g)

H = (9u² - u²) / (2g)

H = 8u² / (2g)

H = 4u²/g

Height of the tower is 4u²/g

Answer 2

Answer:

4u²/10

Explanation:

taking g = 10m/s²

by using v²-u² = 2gh

= (3u)² - u² = 20s

= 9u² - u² = 20s

= 8u² = 20s

S = 8u²/20

S = 4u² /10

NOTE : in some cases g is taken as 9.8m/s²

so,we can take it as

S = 4u² / g

Hope it helps you