Question

a stone is thrown vertically upward with an initial velocity of 49 m/s taking g=10 m/s² find the maximum height reached by the stone also find the time taken to reach that height
steps explanation please​

Answer 1

Answer:

Initial Velocity u=40

Fianl velocity v=0

Height, s=?

By third equation of motion

v

2

−u

2

=2gs

0−40

2

=−2×10×s

s=

20

160

⇒s=80m/s

Toatl distance travelled by stone = upward distance + downwars distance =2×s=160m

Total Diaplacement =0, Since the initial and final point is same.