Question

A stone is thrown vertically upward with an initial velocity of 25m/s , calculate time taken to reach the maximum height?

Answer 1

Answer:

2.65 seconds

Explanation:

Given:

u = 26 m/s

v = 0 m/s (At highest point)

a = g = -9.8 m/s²   ∵ the throw is against gravitational pull

t = ?

We can obtain it from the first equation of motion which says:

v = u + at

0 = 26 + (-9.8)(t)

t = $\frac{26}{9.8}$

≈2.65 seconds