Physics, asked by shivigupta2491, 1 year ago

A stone is thrown vertically upward with an initial velocity v0.The distance travelled in time 4v0/3g is

Answers

Answered by Tamash
10
Hey mate here is ur solution...

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As the acceleration due to gravity is -g

hence travelled distance can be found by formula s = ut +½at²

travelled height in 4v0/3g sec is

H= v0*4v0/3g -½g *(4v0/3g )²

=4v0²/3g-½g* 16v0²/9g²

= 4v0²/3g -8*v0²/9g

=4v0²/9g this is travelled distance in given time

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Hope this will help you...
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