A stone is thrown vertically upward with an initial velocity of 40m/s. Taking G = 10m/s², find the maximum height reached by the stone. What is the net displacement and the total distance covered by the stone.
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Answers
Answer:
The maximum height is 80 m and the total distance covered by the stone is 160 m and the displacement is zero.
Explanation:
Given that,
Final velocity v = 0
Initial velocity u = 40m/s
We know that,
Using equation of motion
The maximum height is
The stone will reach at the top and will come down
Therefore, the total distance will be
The net displacement is
Hence, The maximum height is 80 m and the total distance covered by the stone is 160 m and the displacement is zero.
Step-by-step explanation:
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Answer:
Initial Velocity u=40
Fianl velocity v=0
Height, s=?
By third equation of motion
v
2
−u
2
=2gs
0−40
2
=−2×10×s
s=
20
160
⇒s=80m/s
Toatl distance travelled by stone = upward distance + downwars distance =2×s=160m
Total Diaplacement =0, Since the initial and final point is same.
Step-by-step explanation:
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