A stone is thrown vertically upward with an initial velocity of 40 m/s.
Taking g = 10 m/s2, find the maximum height reached by the stone. The stone
comes back to initial position.What is the net displacement and the total
distance covered by the stone
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Answer:
Answer: The maximum height is 80 m and the total distance covered by the stone is 160 m and the displacement is zero.
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