Question

A stone is thrown vertically upward with an initial velocity of 40 m/s. Taking g = 10 m/s2, find the maximum height reached by the stone. What is the net displacement and the total distance covered by the stone?​

Answer 1

hey mate

here is your answer...

Answer:

GIVEN:

u=40 m/s

g=10 m/s²

thus,

v²=u²-2gh

0²=40²-2*10*h

20h=1600

h=80 m (answer)

after reaching the maximum height , the stone falls back to ground.

so, the net displacement is 0(as final and initial position is same)

the distance=2h

=2*80=160 m(answer)

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Answer 2

Answer:

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