Question

A stone is thrown vertically upward with an initial velocity of 40m/s.Draw the velocity-
time graph of the motion of stone till it comes back on the ground.
i )Find the total distance covered and net displacement by the stone.
ii )Use the graph to find the maximum height reached by the stone.​

Answer 1

Answer:

Here it is:

Explanation:

Answer 2

where V = 0

U = 40 m/s

a = -g m/s² = -10 m/s²

0 = (40)² -2 × 10 × S

• S = 80 m .