Question

A stone is thrown vertically upward with an mit
the maximum height
covered by the stone when it falls back to the ground?
cally upward with an initial velocity of 40 m/s. Taking g = 10 m/s", find
by the stone. What is the net displacement and the total distance
n
iven that the mass of the

Answer 1

Explanation:

According to the equation of motion under gravity v2 − u2 = 2gs Where, u = Initial velocity of the stone = 40 m/s v = Final velocity of the stone = 0 m/s s = Height of the stone g = Acceleration due to gravity = −10 ms−2 Let h be the maximum height attained by the stone. Therefore, 0 2 − 402 = 2(−10)ℎ ⇒ ℎ = (40×40) / 20 = 80 Therefore, total distance covered by the stone during its upward and downward journey = 80 + 80 = 160 m Net displacement during its upward and downward journey = 80 + (−80) = 0.

Answer 2

Explanation:

Now , learn more information

what is acceleration due to gravity ?

A free-falling object has an acceleration of 9.8 m/s/s, downward (on Earth). ... The numerical value for the acceleration of gravity is most accurately known as 9.8 m/s/s. There are slight variations in this numerical value (to the second decimal place) that are dependent primarily upon on altitude.

Thank You

have a nice day ❤