Question

a stone is thrown vertically upward with initial velocity of 20 metre per second taking ji as a 10 metre per second find the maximum height reached by the stone find the net displacement and total displacement covered by the stone in 4 second​

Answer 1

u = 40 m/s 

As the stone is thrown upward the acceleration due to gravity is to be taken negative.

g = - 10 m/s2 

v2 - u2 = 2as

For free fall we can write this equation as,

v2 - u2 =2gh

As the stone reaches the maximum height its final velocity v =0

Thus,

0 - (40)2 = 2× (-10) × h 

- 1600 = -20 × h 

h = 80 m 

So, the maximum height to which the stone can reach is 80 m.

 

The total distance covered by the stone = 80 + 80 = 160 m 

And as th stone comes back to its initial position the displacement of the stone = 0