Question

a stone is thrown vertically upward with speed of 20m/s.how highwill it go before it begins to tall.

Answer 1

HEY DEAR ...

Velocity at maximum height (v) = 0
Acceleration = -g
(-ve sign because it’s in the direction opposite to motion of stone)

v² - u² = 2aS

S = v² - u² / (2a)
= [0 - (20 m/s)²] / [2 × (-9.8 m/s²)]
= 20.40 m

It will reach a height of 20.40 m before it begins to fall.

HOPE , IT HELPS ...