A stone is thrown vertically upward with speed of 5m/s.How high does the stone rise before returning back to earth.Given Accelaration=9.8m/s^2
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Explanation:
at heighest point v=0
u=5m/s
v²=u²-2gs
0²=25-19.6s
19.6S=25
S=25/19.6=1.277m
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