Question

A stone is thrown vertically upward with the speed of 10m/s. The stone reaches the maximum height of 5m. Calculate the time taken to reach the maximum height and velocity of the stone at that point.

Answer 1

use
this .
Give :::::
speed=10m/s
hight =5m
time=?
gravity =9.8 ×10^4

v=u-gt
10=0-9.8 ×t
t=.98 sec

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THANKS

Answer 2

Given:

Initial velocity (u) = 10 m/s

Acceleration = - 10 ms^-2 (in the direction opposite to the direction of motion of the stone)

Maximum height = 10 m.

To Find:

The time taken to reach the maximum height,

Velocity of the stone at that point.

Solution:

Final velocity (v) = 0 m/s (since the stone will reach a state of rest at the point of maximum height).

According to the first motion equation,

v = u + at

Therefore, time is taken by the stone to reach a position of rest (maximum height) = (v – u) /a

= (0 – 10)/ (-10 s)

Time taken = 1 second.

The stone reaches a maximum height of 5 meters in a timeframe of 1 second. The velocity of the stone at that point is 0 m/s.