A stone is thrown vertically upward with the speed of 20m/s .How high will it goes before it begins to fall . (g=9.8 m/s)
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u = 20m/s; v = 0m/s; g = -9.8m/(s) square (g is negative as acceleration is in opposite direction, i.e. upwards)
v = u + gt
=> t = v-u/g
= 0-20/-9.8 = -20/-9.8 = 2.04s
h = ut + g(t) square / 2
= (20)(2.04) + (-9.8)(2.04)(2.04)/2
= 40.08 - 20.39
= 19.69 m
So, the stone will travel 19.69 m before it begins to fall.
Hope it helps you! Please mark it as brainliest!
v = u + gt
=> t = v-u/g
= 0-20/-9.8 = -20/-9.8 = 2.04s
h = ut + g(t) square / 2
= (20)(2.04) + (-9.8)(2.04)(2.04)/2
= 40.08 - 20.39
= 19.69 m
So, the stone will travel 19.69 m before it begins to fall.
Hope it helps you! Please mark it as brainliest!
Virtulya:
Pls mark the answer as brainliest...
And how do I do it .I am a new user
I suppose the option will come to you once somebody else answers the question or it will come automatically after sometime.
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4
Answer:
answer is 20m........
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