Question

A stone is thrown vertically upward with the velocity of 20m/s. find the maximum height reached by the stone and the total time of flight​

Answer 1

Answer:

u=20m/s

v=0m/s

accleration is not given so we take 9.8m/s^ and it will be negative as it is in upward direction (opposite) .

a=-9.8m/s^2

v^2-u^2=2as

0^2-20^2=2×(-9.8)s

-400=-19.6s

400/19.6=s

s=20.4m

v=u+at

0=20+(-9.8)t

-20=-9.8t

20/9.8=t

2.0sec

total time is 2+2 =4 seconda