Question

A stone is thrown vertically upward with the velocity of 25m/s . how long does it take to reach the maximum height? also calculate the height.

Answer 1

Answer:

u=25ms−1u=25ms−1

v=0ms−1v=0ms−1

a=−9.8ms2a=−9.8ms2

v=u+atv=u+at

=>0=25+(−9.8)∗t=>0=25+(−9.8)∗t

=>t=25/9.8=>t=25/9.8

=>t=2.55sec=>t=2.55sec

v2−u2=2ahv2−u2=2ah

=>0−625=2∗(−9.8)∗h=>0−625=2∗(−9.8)∗h

=>h=625/19.6=>h=625/19.6

=>h=31.89m=>h=31.89m

Time taken to reach maximum height = 2.55 sec

Maximum height attained = 31.89 m

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