Question

a stone is thrown vertically upward with velocity 4m/s. Find the maximum height reached by the stone. Also find the velocity after 2 sec​

Answer 1

Explanation:

Initial speed=u=28m/s

Final velocity at maximum height=v=0m/s

a=g=10m/s

2

A) maximum height attained by stone=u²/2g=28×28/2×10=39.2m

B) time=t=u/g=28/10=2.8sec

t1=2.85−1=1.85

V=u+at

=28−(10)(1.85)=28−18.13=9.87m/s

Hence the velocity is 0.87 m/s

c) No it will not change .

Because after 1-sec final velocity becomes zero for any initial velocity