A stone is thrown vertically upward wlith speed 10m/s from the edge of a cliff 65m high.what will be its speed just before hitting the ground
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v-initial=10m/s
v-final =(v-initial)+root(2gh)
=10+root(2×10×65)
=46.07
v-final =(v-initial)+root(2gh)
=10+root(2×10×65)
=46.07
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