A stone is thrown vertically upwards and it is caught after time ‘t’ seconds, then the maximum height reached by it is ?
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3
Answer:
Let the initial velocity is u, maximum height is h. Time taken in upward motion = Time taken in downward motion = t0/2.
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Answered by
1
Answer:
let the initial velocity is u , maximum height is h
velocity at maximum height = 0
time taken is upward motion = time taken in downward motion = t0/2
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