Question

A stone is thrown vertically upwards at a speed of 40 m/s. Calculate the time interval for which the particle is 40 m above the ground.

1. 4√2s
2. 8s
3. 4s
4. 2√2s


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Answer 1

Initial velocity (u)= 40m/s

displacement(s)=40m

final velocity =0m/s

acceleration(a) =10m/s^2

time(t) =?

we have,

v=u+at

0=40-10t {a=g(g=negative) }

-40=-10t

t=4s answer