Question

A stone is thrown vertically upwards from the ground
and caught at the same point on the ground after 10
seconds. (Take, g = 10 m/s2)
The time taken by the stone to reach the highest point
is
1
5 sec
2
10 sec
3
9 sec
4
6 sec​

Answer 1

Answer:

Let the initial velocity be u, maximum height is h.

Velocity at maximum height v=0

Time taken in upward motion=Time taken in downward motion

=2t0

For upward motion,

v=u−gt

u=2gt0

h=ut−2gt2

h=2gt02t0−21g2t02

h=8gt02