Physics, asked by nisant18, 1 month ago

A stone is thrown vertically upwards from the ground. It returns to the ground after 4 s. What was the speed with which it was thrown upwards? (g = 10 m/s²)​

Answers

Answered by janhavishelke927
0

Explanation:

If it takes 4s to return, then (ignoring fiction, etc.) it took 2 seconds to reach its maximum height — where is velocity is zero.

Since gravity steals about 10 m/s from upward velocity, for each second of travel, the initial velocity must have been 20 m/s.

Therefore, the AVERAGE VELOCITY was 10 m/s for the 2 seconds of ascent.

Multiplying 10 m/s by 2 s, the height was 20m.

Answered by pdayanand453
0

Answer:

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