Question

a stone is thrown vertically upwards such that it reach the maximum height of 20m. Calculate the initial speed of the stone. Consider the value of acceleration due to 10m/s^2​

Answer 1

Given:

• Distance (h) = 20m
• Acceleration due to gravity (g) = 10m/s²
• (v) = 0 m/s

To Find:

• Calculate the initial speed of the stone?

Formula Used:

We can Use the Third Equation of Motion;

$\\ \bigstar{\underline{\boxed{\tt\large{ \green{ v^2 = u^2 + 2gh} }}}}$

Where

• g = Acceleration die to Gravity
• h = distance

Solution:

After substituting values,

$\implies$ v² = u² + 2gh

$\implies$ (0)² = u² + 2gh

$\implies$ 0 = u² + 2 × 10 × 20

$\implies$ 0 = u² + 400

$\implies$ -400 = u²

$\implies$ u = $\sqrt{-400}$

$\implies$ u = -20 m/s

Hence,

• The Initial Velocity of the stone is 20 m/s.