A stone is thrown vertically upwards to break a
mango from the tree, at a height of 20 m from
the ground. If it takes 2 sec to reach the mango,
the initial speed of the stone, with which it was
thrown upwards is m/s. (take g = 10
m/s2)
20
Answers
Answered by
1
Use Newton’s 2nd law
force = mass * acceleration
F = ma
for gravity on Earth, ma = -mg
You can equate this to the initial velocity like this:
a = (final velocity - initial velocity) / time
At max height, the velocity is 0, so
a = (0 - 20) / time = -20 / time
so going back to Newton’s 2nd law
m * -20 / time = -mg
g is a constant on Earth, 9.8 m/s^2
Divide both sides by -m and rearrange for time
Time = 20 / 9.8 = about 2 seconds
hope it will help you..
Answered by
2
Answer:
A stone is thrown vertically upwards to break a
Explanation:
A stone is thrown vertically upwards to break a
mango from the tree, at a height of 20 m from
the ground. If it takes 2 sec to reach the mango,
the initial speed of the stone, with which it was
thrown upwards is m/s. (take g = 10
m/s2)
20
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