Question

a stone is thrown vertically upwards .when stone is at a height half of its max height its speed i s 10m/s then the max height attained by the stone is?

Answer 1

Answer:

ANSWER

Let u be the initial velocity and h be the maximum height attained by the stone.

v

1

2

=u

2

−2gh,

(10)

2

=u

2

−2×10×

2

h

100=u

2

−10h ....(i)

Again at height h,

v

2

2

=u

2

−2gh

(0)

2

=u

2

−2×10×h

u

2

=20h ... (ii)

So, from Eqs. (i) and (ii) we have

100=10h

h=10m

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Answer 2

Answer:

Explanation:

Let u be the initial velocity and h be the maximum height attained by the stone.

v ₁ ² = u²−2gh,

(10)²=u²−2×10× h/2

​100=u²-10h ....(i)

Again at height h,

v₂² = u²−2gh

(0)² =u²−2×10×h

u²=20h  ... (ii)

So, from Eqs. (i) and (ii) we have

100=10h

h=10m

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