Question

a stone is thrown vertically upwards with a intial velocity
of 14 ms^-2 .find the maximum
height reached and the time of ascent ,given g2 = 9.8 Ms ^-2
please please ,..........​

Answer 1

Answer:

Max height = v²/2g

hence, 14²/9.8

i.e. 196/9.8 = 20m

Explanation:

The above method shows that max height is 20m

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