a stone is thrown vertically upwards with a speed of 20 milliseconds the time in seconds taken by it to come back to its position of projection is
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Answer:
2 *10 power minus 3 seconds
Step-by-step explanation:
s = ut + 1/2 at2
u = 0, ut = 0
when it comes down accelaration acting downwards is 'g'
g = 10 m/s2 (aprox)
1/2. 10. 20 .20. 10 power minus six ( milli seconds to seconds)
ans is 2*10 power minus 3 seconds
Answered by
0
Answer:2*10power minus 3second is the answer
Step-by-step explanation:
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