A stone is thrown vertically upwards with a speed of 20 metre per second how high is will go before it begins o fall
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Answered by
8
u can find it by the equation
v^2=u^2+2as
v^2=u^2+2as
Answered by
10
Use v^2 - u^2 = 2aS
You’ll get
H = u^2 / (2g)
= 20^2 / (2 * 10)
= 20 m
It will go 20 m high before it begins to fall.
[Note: I took g = 10m/s^2 for simplification]
You’ll get
H = u^2 / (2g)
= 20^2 / (2 * 10)
= 20 m
It will go 20 m high before it begins to fall.
[Note: I took g = 10m/s^2 for simplification]
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