A stone is thrown vertically upwards with a speed of 20 m/s. How high will it go before it begins to fall ? (g = 9.8 m/s^2)
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Answered by
2
Maximum height of the stone before it fall.
★ H = U²/(2 g)
= 20²/(2 x 9.8)
= 20.4 m
Answered by
0
Answer:
It will reach a height of 20.40 m before it begins to fall
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