Question

A stone is thrown vertically upwards with a speed of 20 m/s. How high it will go before it begins to fall? (g=9.8 m/s^2 )

Answer 1

Hi !

Initial velocity = u = 20 m/s 

Final velocity = v = 0              [ at maximum height , v = 0 ]

Acceleration due to gravity(g)  in this case , is taken as negative.

This is because , when the direction of motion of object is opposite to "g" , then value of g is taken as -ve

hence ,

g = -9.8 m/s²

Let's use the formula :-

[h = height ]

v² -u² = 2gh

0² - 20² = 2*-9.8*h

-400 = -19.6h

h = -400/-19.6

  = 20.408 m [ approximately ]

The stone will go 20.408 metres high  before it begins to fall

:) :) :) :) :)

Answer 2

Answer:

Hey mate I didn't understand

What we have to do here

plz

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