Question

a stone is thrown vertically upwards with a speed of 20 m/s. how high will it go before it begins to fall (g=9.8 m/s^2​

Answer 1

Answer :

A ball is thrown vertically upward at a speed of 20m/s$.$

We have to find maximum height attained by stone.

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For a body thrown vertically upward, g is taken negative.

Since constant acceleration due to gravity acts on the stone throughout the motion, we can apply equation of kinematics to solve this question.

Speed of stone at highest point = zero

◈ Third equation of kinematics :

⇒ v² = u² + 2gH

⇒ 0² = 20² + 2(-9.8)H

⇒ H = -400/-19.6

⇒ H = 20.4 m

Hence, maximum height attained by stone is 20.4m.