Question

a stone is thrown vertically upwards with a speed of 5 metre per second how high does the stone rise before returning back to the earth give equation due to Earth's surface g= 9.8 metre per second​

Answer 1

Intial Velocity (u)=5 m/s

Final Velocity at maximum Height (v)=0 m/s

Acceleration due to Gravity (a)=-9.8 m/s²

Approx=-10 m/s²

Maximum Distance It reached=s

Here Acceleration is negative because Due to Gravity Pull it's Speed Will be slower

Use Equation of Motion

v²=u²+2as

Where

v=Final Velocity

u=Intial Velocity

a=Acceleration

s= Maximum Distance

${0}^{2} = {5}^{2} + 2 \times - 10\times s \\ \\ 0 = 25 + (- 20s) \\ \\ 0 - 25 = - 20s \\ \\ - 25 = - 10s \\ \\ s = \frac{ - 25}{ - 20} = 1.25$

Maximum Distance It reach=1.25 m

*When Something Is Throw upward Due to Gravity It's Speed Become Slow and At maximum height it Velocity become 0 and Then It start falling Back on ground*

Height=1.25 m

Answer 2

Answer=1.275 seconds

Explanation

Given that - Final velocity (v) 0 m/s

Initial velocity (u) 5m/s

USE THIRD EQUATION OF MOTION

(v)square = (u)square + 2as

0square = 5square + 2 (-9.8) s

0 = 25 + (-1.96) s

0-25 = -1.96s

-25 = -1.96s

1.96s = 25

s = 25÷1.96

s = 1.275 seconds