A stone is thrown vertically upwards with a speed of 5 ms-1. A how high does the stone rise before returning back to the earth?
given acceleration due to earth's attraction,g=9.8 ms-1
plz give me ans.
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Answered by
3
Answer:
use third equation of motion
s=v²-u²/2a
s =0 -5²/2x9.8
= 0-25/ 19.8
25/19.8
25x10/19.8x 10
250/198
simplify u will get
hope this will help
Explanation:
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Explanation:
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