Question

A stone is thrown vertically upwards with a vel 4m/s it will return to the groind witg a vel

Answer 1

it returns back the same velocity of 4 m/s

bcz time of ascent equal to time of decent

hope it will help you
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Answer 2

$\mathbb{\huge{Heya !}}$

$<b>Here's your answer !!$

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When a stone is thrown vertically upward :

Initial velocity ( u ) = 4m/s

Final velocity ( v ) = 0

Acceleration due to gravity ( g ) = - 10 m/s²

{ g is negative because the stone is thrown upward opposite to the force of gravity }

Time ( t ) = ?

We know ,

$\bf = > \: g \: = \: \frac{v \: - \: u}{t} \\ \\ \: \bf = > \: - \: 10 \: m {s}^{2} \: = \: \frac{0 \: - \: 4}{t} \\ \\ \bf = > \: - \: 10m {s}^{2} \: = \: \frac{ - \: 4}{t} \\ \\ = > \bf \: t \: = \: \frac{ - \: 4}{ - \: 10} \\ \\ = > \bf \: time \: = \: 0.4 \: s$

When the stone returns to the ground,

Initial velocity ( u ) = 0

Final velocity ( v ) = ?

Acceleration due to gravity ( g ) = 10 m/s²

Time = 0.4 s
$\bf = > \: g \: = \: \frac{v \: - \: u}{t} \\ \\ \: \bf = > \: 10 \: m {s}^{2} \: = \: \frac{ v \: - \: 0}{0.4} \\ \\ \bf = > \: 10m {s}^{2} \: = \: \frac{ v}{0.4} \\ \\ = > \bf \: v \: = \: 10 \: \times \: 0.4 \\ \\ = > \bf \: final \: velocity\: = \: 4 \: m {s}^{ - 1} \:$

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Thanks !!