A stone is thrown vertically upwards with a velocity of 10m/s from the edge of a cliff 120m high. How long will it take for a stone to reach the ground at the foot of the cliff?
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Firstly
The stone goes upward and then downward , in this process it takes 2 secs
And
Then by,using s=ut + 1/2ut sq
120=10t+1/2×10tsq
120=10t+5tsq
t= 4sec
Therefore total time= 6 secs
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